It will be difficult to answer this question accurately without knowing "the expression below."
It is (7x+5)(2x-7) when factored
-2x(x + 3)(x - 2)
-(3x - 4)(x - 2)
(x + 5)(x - 8)
(x + 7)(x - 6)
2x^2
-2x(x + 3)(x - 2)
It is (7x+5)(2x-7) when factored
(2x+7)(x+7)
(x + 1)(x + 5)
If you mean: 2x2+15x+25 then it is (2x+5)(x+5)
-x2 + 2x + 48 = (-x - 6)(x - 8)
To factor the trinomial (7x^2 + 7x - 14), first factor out the common factor of 7: [ 7(x^2 + x - 2) ] Next, we can factor the quadratic (x^2 + x - 2) into ((x + 2)(x - 1)). Thus, the complete factorization of the original trinomial is: [ 7(x + 2)(x - 1) ]
it is below 555 and above 200 * * * * * x3 - 2x2 + 35x = x*(x2 - 2x - 35) = x*(x + 5)*(x - 7)
(x + 5)(x - 8)
-(3x - 4)(x - 2)
-(x + 13)(x - 2)