8,10,12
16, 17 and 18
6 and 8. 6 * 8 = 48 6 * 6 = 36 48 - 36 = 12
Let the smaller number be n then the other number is (n + 2). Then, n(n + 2) = 783 n2 + 2n = 783......which can be rearranged as : n2 + 2n - 783 = 0 This can be factored : n2 + 2n - 783 = (n + 29)(n - 27) = 0 The solution that concerns us is when n is positive. This occurs when, n - 27 = 0 : n = 27. Then the two consecutive odd numbers are 27 and 29.
A positive number is any number greater than zero. 1 is a positive number, so is 2, 2.5, 3.14159, 11, 11.25 etc 0.5 is a positive number. The product of two positive numbers is the result of multiplying them together. * 2 x 3 = 6 (the product). In this case the product is greater than either number. But... * 0.5 x 0.25 is 0.125. ~In this case the product is actually smaller than either of the two numbers! * Or 0.5 x 10 = 5 . Here the product is greater than 0.5 but smaller than 10. So the answer is ...sometimes!
The product of 2 consecutive positive number is 48. Find the 2 numbers
5
It is 23.
There are none. However, there are two consecutive positive odd numbers: 25 and 27.
The sum of the squares of two consecutive positive numbers is 41.What is the smaller number?Improved Answer:-It is 4 because 42+52 = 41
Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.
The numbers are 5 and 6.
The product of two consecutive positive integers can be found by multiplying the smaller integer by the larger integer. If the smaller integer is represented as ( n ), then the larger integer would be ( n + 1 ). Therefore, the product of two consecutive positive integers is ( n \times (n + 1) ).
4
There are none.
5.
4