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Q: Find 4 consecutive even integers where the product of the smaller two numbers is 56 less than the product of the two larger numbers?

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The numbers are 11, 13, 15 and 17.

The product of 2 consecutive positive number is 48. Find the 2 numbers

The smaller of the two numbers is 31.

In 'normal' arithmetic, there is no solution of 3 consecutive odd numbers where the product of the smaller two is 22 less than that of the larger two. For instance difference in products for 1-3-5 is 12, for 3-5-7 it is 20, and for 5-7-9 it is 28. The series steps by 8 integers for each set of 3 odd numbers investigated.

The four even integers are 4, 6, 8, and 10. 10 x 8 = 80 6 x 4 = 24 80 - 24 = 56

Related questions

The numbers are 11, 13, 15 and 17.

The product of 2 consecutive positive number is 48. Find the 2 numbers

They are 6, 8, 10 and 12.

The smaller of the two numbers is 31.

13 and 12 are the two integers that have the product of 156 and 12 is the smaller of the two.

Smaller number is '6'

It is 23.

You can solve this in two ways.1) Trial and error. That is, try multiplying two consecutive integers; if the product is too large, try smaller integers; if the product is too small, try larger consecutive integers. 2) Call the two consecutive integers "n" and "n+1", and solve the equation: n(n+1)=210

44 & 45

-1

The numbers are 9 and 10.

6 x 8 = 48 10 x 12 = 120 120 - 48 = 72

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