There are none.
14, 15, 16 and 17.
Let's denote the four consecutive integers as n, n+1, n+2, and n+3. The sum of these integers can be represented as n + (n+1) + (n+2) + (n+3) = 4n + 6. Given that the sum is -66, we can set up the equation 4n + 6 = -66. Solving for n, we find that n = -18. Therefore, the four consecutive integers are -18, -17, -16, and -15.
The numbers are -18, -17, -16 and -15.
The numbers are -21, -19, -17 and -15.
11, 13, 15, and 17
The integers are 15 and 17.
The sum of the squares of the three consecutive integers 11, 13, 15 = 515
Divide the sum of the three consecutive odd integers by 3: 45/3 = 15. The smallest of these integers will be two less than 15 and the largest will be two more than 15, so the three consecutive odd integers will be 13, 15, and 17.
The integers are 13 and 15.
The integers are 11, 13 and 15.
15 and 17
17