0
Still curious? Ask our experts.
Chat with our AI personalities
Maxine
Lao
SteveAdd your answer:
Earn +20 pts
What are the two positive integers that have a product of 98 where one integer is twice the other?
The integers are 14 and 7.
The larger of 2 positive integers is 5 more than twice the smaller integer The product of the integers is 52 find the integers?
y=2x+5 xy=52 x(2x+5)=52 2x2+5x-52=0 (2x+13)(x-4)=0 x=-6.5 or x=4 Since you specified positive integers, x=4. y=2*4+5=13 So, the two numbers are 13 and 4.
One integer is three more than twice another integer If the sum of the two integers is 36 what is the smaller integer?
ok this is what it looks like to me...I definitely could be wrong. one integer is three more than twice another integer if one integer is three more than another number (x+3=y) Then you just multiply "the other number" by 2. (x+3=2*y) Sum of two integers is 36....so add them (x+y=36) Solve that equation for one number so...(y=36-x) Then you would plug that equation into the first equation where there is a y: (x + 3 = 2*(36-x))
The sum of two numbers is 70 The larger number is 4 more than twice the smaller number Whta is the smaller number?
16.5
How would you find 3 consecutive integers such that twice the third is 15 more than the first?
Let's denote the first integer as x. The next two consecutive integers would be x+1 and x+2. According to the given condition, twice the third integer (2(x+2)) is equal to 15 more than the first integer (x+15). Setting up the equation: 2(x+2) = x + 15. Solving this equation will give you the first integer, which you can then use to find the consecutive integers.
