2(x - 5y)
Assuming you mean 30y^3 and 20y^2, We ought to factorise to check our answers. The greatest number that divides into both 30 and 20 is 10. The greatest y term that divides into both y^3 and y^2 is y^2 So, 10y^2 (3y + 2) If we multiplied out brackets above, we would be left with 30y^3 + 20y^2 Since (3y +2) cannot be simplified any further, Ans = 10y^2
0
(y - 8)(y - 2)
The LCM is 40y3
The greatest common factor of 10y plus 15 is 5.
10x+10y+100 There is a common 10 in each number. 10(x+y+10)
2(x - 5y)
x2 + 10y + 25 doesn't factor neatly. If that was x2 + 10x + 25, it would factor to (x + 5)(x + 5) or (X + 5)2
Assuming you mean 30y^3 and 20y^2, We ought to factorise to check our answers. The greatest number that divides into both 30 and 20 is 10. The greatest y term that divides into both y^3 and y^2 is y^2 So, 10y^2 (3y + 2) If we multiplied out brackets above, we would be left with 30y^3 + 20y^2 Since (3y +2) cannot be simplified any further, Ans = 10y^2
Clearly, both terms have 5 as a factor. If you divide by 5, you get the other factor:5+10y = 5(1 + 2y)This can't be further factored.
0
(y - 8)(y - 2)
2(3y + 1)(y - 2)
The LCM is 40y3
2y-10y
10x-10y = 0