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What 3 digit-number is divisible by 4?
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Is 619 odd or even?
If the last digit of a number is 0, 2, 4, 6, 8 or 0 then the number is divisible by 2. The digit of 619 is 9, so 619 is not divisible by 2.
What number between 120 and 130 is divisible by 3 and has a digit sum divisible by 4?
To find a number between 120 and 130 that is divisible by 3 and has a digit sum divisible by 4, we first consider the numbers in that range: 121, 122, 123, 124, 125, 126, 127, 128, 129. Next, we calculate the digit sum of each number: 121 (1+2+1=4), 122 (1+2+2=5), 123 (1+2+3=6), 124 (1+2+4=7), 125 (1+2+5=8), 126 (1+2+6=9), 127 (1+2+7=10), 128 (1+2+8=11), 129 (1+2+9=12). Therefore, the number between 120 and 130 that is divisible by 3 and has a digit sum divisible by 4 is 123.
Is 189 divisible by 2 3 4 5 6 9 and 10?
No. 189 is only evenly divisible by 3 and 9 (from the set provided). Using the following rules of divisibility on the number 189: Divisible by 2? No - the number is not even Divisible by 3? Yes - the sum of the digits (1 + 8 + 9 = 18) is divisible by 3 Divisible by 4? No - the last two digits are not evenly divisible by 4 Divisible by 5? No - the last digit is not a 0 or a 5 Divisible by 6? No - the number is not even Divisible by 9? Yes - the sum of the digits is divisible by 9 Divisible by 10? No - the number is not divisible by 2 or 5
Is 646 divisible by 9?
6 + 4 + 6 = 16 1 + 6 = 7 → No; 646 is not divisible by 9 (there is a remainder of 7). ----------------------------------------- Only if the sum of the digits is divisible by 9 is the original number divisible by 9. Repeat the test on the sum until a single digit remains; only if this single digit is 9 is the original number divisible by 9, otherwise this single digit is the remainder when the original number is divided by 9.
