Q: What 2 digit number divisible by 4 6 7?

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If the last digit of a number is 0, 2, 4, 6, 8 or 0 then the number is divisible by 2. The digit of 619 is 9, so 619 is not divisible by 2.

129.129.129.129.

No. 189 is only evenly divisible by 3 and 9 (from the set provided). Using the following rules of divisibility on the number 189: Divisible by 2? No - the number is not even Divisible by 3? Yes - the sum of the digits (1 + 8 + 9 = 18) is divisible by 3 Divisible by 4? No - the last two digits are not evenly divisible by 4 Divisible by 5? No - the last digit is not a 0 or a 5 Divisible by 6? No - the number is not even Divisible by 9? Yes - the sum of the digits is divisible by 9 Divisible by 10? No - the number is not divisible by 2 or 5

6 + 4 + 6 = 16 1 + 6 = 7 → No; 646 is not divisible by 9 (there is a remainder of 7). ----------------------------------------- Only if the sum of the digits is divisible by 9 is the original number divisible by 9. Repeat the test on the sum until a single digit remains; only if this single digit is 9 is the original number divisible by 9, otherwise this single digit is the remainder when the original number is divided by 9.

Related questions

smallest 4-digit number divisible by 2 = 1000

12 is the smallest 2 digit number divisible evenly by 4

There is no 4-digit number that is divisible by zero.

1002 is the smallest 4 digit number divisible by 3 and 2.

If the last two digits are divisible by 4 then the number is divisible by 4. Thus, if the tens digit is even and the units digit is 0 or 4 or 8 OR if the tens digit is odd and the units digit is 2 or 6 then the number is divisible by 4.

I am a 3 digit number divisible by 7 but not 2 the sum of my digits is 4 what number am I

Yes. If the last digit is even (ie one of 0, 2, 4, 6, 8) then the whole number is divisible by 2. The last digit is 4, so the number is divisible by 2.

A number which which ends with a 2 digit number that is divisible by 4. For example, 1028 ends with 28 which is divisible by 4.

144 is divisible by 2, 3, 4, 6, 9 and not divisible by 5 or 10.Divisible by 2The whole number is divisible by 2 if the number is even which is shown by the last digit being divisible by 2. The last digit of 144 is 4 and 4 is divisible by 2, thus 144 is divisible by 2.Divisible by 3The number is divisible by 3 if the sum of its digits is also divisible by 3. Sum of the digits of 144 is 1+4+4 = 9 which is divisible by 3, thus 144 is divisible by 3Divisible by 4The number is divisible by 4 is the last two digits is also divisible by 4. Last two digits of 144 are 44 which are divisible by 4, thus 144 is divisible by 4An alternative test: If the last digit plus twice the preceding digit is divisible by 4 then the whole number is divisible by 4.For 144, last digit + twice preceding digit is 4+2x4 = 12 which is divisible by 4, so 144 is divisible by 4Divisible by 5If the last digit is 0 or 5 then the number is divisible by 5 Last digit of 144 is 4 which is neither 0 nor 5, thus 144 is not divisible by 5Divisible by 6To be divisible by 6, the number must be divisible by both of 2 and 3. 144 is divisible by both 2 and 3 (see above), thus 144 is divisible by 6Divisible by 9If the sum of the digits of the number is divisible by 9, then the original number is divisible by 9. For 144, 1+4+4 = 9 which is divisible by 9, thus 144 is divisible by 9Divisible by 10To be divisible by 10, the last digit must be 0. The last digit of 144 is 4 which is not 0, thus 144 is not divisible by 10

Yes. To check if a number is divisible by 4, if the last 2 digits (as a number) are divisible by 4, so is the original number. 32 = 4 x 8 so as 32 is divisible by 4, so is 211032. An alternative test for 4: add the last digit to twice the preceding digit, and if this sum is divisible by 4 so is the original number. This can be repeated until a single digit remains which must be 4 or 8 (to be divisible by 4) if the original number is divisible by 4. for 211032: 2 + 3x2 = 8 → [single digit 8 which] is divisible by 4, so 211032 is also divisible by 4.

1000

How about: 12