It takes four. 3 x 3 x 3 x 3 = 81
To find the highest common factor (HCF) of 81, 243, and 1215, we first need to find the prime factorization of each number. The prime factorization of 81 is 3^4, 243 is 3^5, and 1215 is 3^5 * 5. To find the HCF, we look for the highest power of each prime factor that appears in all the numbers. In this case, the highest power of 3 that appears in all three numbers is 3^4, so the HCF of 81, 243, and 1215 is 81.
The only prime numbers between 81 and 90 is... 83
They are: 79+2 = 81
36 is 4 9ths of 81.
81 and 9 if you add them. 4 and 25 if you multiply them.
9 x 9 = 81 :(
Negative 9 times 9= Negative 81
It depends on what average you want to find. To find the mean of 81, 81, 98, and 91 add the numbers together and divide by 4 (the number of numbers you added). 81 + 81 + 98 + 91 = 351 351 divided by 4 = 87.75. To find the median, list the numbers in order and find the one in the middle. 81, 81, 91, 98 81 and 91 are in the middle. To find the mode, look for the number that appears the most, 81 appears twice and the other numbers appear once. 81 is the mode.
There are not two INTEGERS that can add to make 9 and multiply to make 4, however there are some irrational numbers that will do the job. Let x and y be the two numbers. x + y = 9 xy = 4 so y = 4/x x + 4/x = 9 x² + 4 = 9x x² - 9x + 4 = 0 using the quadratic formula, x = (9 ± √[81-4(1)(4)])/2 = (9 ± √{81-16])/2 = (9 ±√65)/2 ≈ 8.531129 or 0.468871 So the two numbers are approximately 0.468871 and 8.531129
There are infinitely many different choices of 3 numbers that add up to 81. 50 + 30 + 1 = 81 40 + 40 + 1 = 81 10 + 11 + 60 = 81 etc.
81 and 4
25 and 81
16, 81, 625, and 2401
1, 4, 9, 16, 25, 36, 42, 64, 81, 100
They are 'square' numbers. 6x6=36, 9x9=81 and 5x5=25. Some other square numbers are 64, 4, 9, 100 & 121
There are 34 = 81 numbers.