Multiply 630 by .25: 630 * .25 = 157.5
There are infinitely many number pairs: Select any number, X, greater than sqrt(630) = 25.1 Let Y = 630/X Then X*Y = X*(630/X) = 630 Since there are infinitely many numbers greater than 25.1 and X can be any one of them, there are infinitely many possible answers.
18 and 630
Find the numbers that include others in their prime factorization: 7, 9, and 10 Multiply them: 630
630 315,2 105,3,2 35,3,3,2 7,5,3,3,2
3150
Multiply 630 by .25: 630 * .25 = 157.5
There are infinitely many number pairs: Select any number, X, greater than sqrt(630) = 25.1 Let Y = 630/X Then X*Y = X*(630/X) = 630 Since there are infinitely many numbers greater than 25.1 and X can be any one of them, there are infinitely many possible answers.
Multiply 63 by 10 is 630
18 and 630
The highest common factor of the numbers 490 and 630 is 70.
Multiply it by 100 and so it is 630%
Find the numbers that include others in their prime factorization: 7, 9, and 10 Multiply them: 630
630
The least common multiple of the numbers 105 and 90 is 630.
It is: 2*3*3*5*7 = 630
630 315,2 105,3,2 35,3,3,2 7,5,3,3,2