x2+9x-36 = (x-3)(x+12) when factored
x2-12x+35 = (x-5)(x-7)
If you mean: x2-12x+35 then it is (x-7)(x-5) when factored
(12x - 6)(12x + 6)
If you are looking for common factors of 12x and 9 it would be 3.
x2 - 12x + 36 = (x - 6)2
x2-12x+36 = (x-6)2
x2+12x+36=0 2x+12x+36=0 14x+36=0 14x=-36 x=-36/14 x=-2 4/7
If you're looking to solve for x, you can do so as follows: x2 + 12x - 6 = 0 x2 + 12x + 36 = 42 (x + 6)2 = 42 x + 6 = ± √42 x = -6 ± √42
=>2x - 12x + 36 = 0 =>10x = 36=>x = 3.6Another contributor's answer:This is a quadratic equation question:x2-12x+36 = 0When factorised:(x-6)(x-6) = 0
x(x - 4)(x + 3)
x=5/2*sqr(3)
x2+12x+28Improved Answer:--x2+12x+28 = (-x+14)(x+2) when factored
x2+12x+5 = 3 x2+12x+5-3 = 0 x2+12x+2 = 0
Let's first reformat it: x2 + y2 - 12x - 8y - 43 = 0 x2 - 12x + 36 + y2 - 8y + 16 = 43 + 36 + 16 (x - 6)2 + (y - 4)2 = 95 So this equation defines a circle, with a center point at (6, 4) and a perimeter (i.e. circumference) of √95.
6.(x2 + 12x + 36) = 6.(x + 6)(x + 6)
x2+9x-36 = (x-3)(x+12) when factored