The first 100 multiples of 3:
3, 6, 9, 12, 15, 18, 21, 24, 27, 30,
33, 36, 39, 42, 45, 48, 51, 54, 57, 60,
63, 66, 69, 72, 75, 78, 81, 84, 87, 90,
93, 96, 99, 102, 105, 108, 111, 114, 117, 120,
123, 126, 129, 132, 135, 138, 141, 144, 147, 150,
153, 156, 159, 162, 165, 168, 171, 174, 177, 180,
183, 186, 189, 192, 195, 198, 201, 204, 207, 210,
213, 216, 219, 222, 225, 228, 231, 234, 237, 240,
243, 246, 249, 252, 255, 258, 261, 264, 267, 270,
273, 276, 279, 282, 285, 288, 291, 294, 297, 300.
They are the first six multiples of 15.
The first 50 multiples of 6 are the first fifty even multiples of 3.
The multiples of 3 to 99 are the following:3,9,12,15,18,21,24,27,30,33,36,39,42,45,48,51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,96 and 99 1 and 100 is not a multiple of 3 so it should be from 3 to 99 :)
what is the ratio of multiples of 3 between 1 and 100 to all numbers between 1 and 100
The first 5 multiples of 3 are as follows: 3, 6, 9, 12, 15
There are 166 multiples in 500 (500/3=166r2)and 33 multiples in100(100/3=33 r1) if you subtract the later from the first.... 166-33=133
No, 99 and 102 are Multiples of 3, it takes 33.33333333, 3's to make 100.
They are the first six multiples of 15.
The first 50 multiples of 6 are the first fifty even multiples of 3.
To determine the number of 3-digit numbers that are multiples of 5, we need to find the first and last 3-digit multiples of 5. The first 3-digit multiple of 5 is 100, and the last 3-digit multiple of 5 is 995. To find the total number of such multiples, we can use the formula (Last - First) / 5 + 1 = (995 - 100) / 5 + 1 = 180. Therefore, there are 180 3-digit numbers that are multiples of 5.
They are the six multiples of 15.
The 3 first multiples of 75 are: 1, 3, and 5.
The first 10 multiples of 100: 100, 200, 300, 400, 500, 600, 700, 800, 900, 1000
What are the first three common multiples of four and five
No factors of 100 are multiples of 3.
101
The sum of the first 10 multiples of 3 is 165.