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7 is a Prime number. The only factors of a prime number are 1 and itself, so 7 only has two factors.

Q: What are the first five factors of 7?

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Just multiply the first five prime numbers! 2x3x5x7x11 = 6x35x11 = 210x11 = 2310. Any multiple of this number "has the first five prime numbers as factors", but 2310 is the smallest such number.

The factors of 15 are:1, 3, 5, 15The factors of 35 are:1, 5, 7, 35The common factors are: 1, 5

There are only three factors of 49, which are 1, 7, and 49. There are only two prime factors of 49, which are 7 and 7. There is only one distinct prime factor of 49, which is 7. There are not ten factors of 49.

Any three-digit multiple of 60, from 120 to 960, has the first five counting numbers as factors.

twelve and minus five 12 x -5 = -60 12 - 5 = 7

Related questions

There are not five prime factors of 7. There is only one prime factor of 7 because 7 is a prime number. The factors of 7 are 1 and 7; the prime factor of 7 is 7.

The first prime numbers are 2, 3, 5, 7, 11. When multiplied together the product is 2310. It is the smallest number that has the first five numbers as its factors.

81 only has five factors.

There are only four factors ! They are 1,2,13 & 26

Nine has three factors.

there are only 2 factors of 7 - 1 and 7 as it is a prime number

16 has only five factors: 1, 2, 4, 8 & 16.

59 is a prime number and therefore does not have any factors.

7 has two different factors. 9 has three different factors. 10 has four different factors. 16 has five different factors. So, the answer is 10.

The only factors of 7 are itself and one because it is a prime number

The factors of 81 are 1, 3, 9, 27, and 81

Just multiply the first five prime numbers! 2x3x5x7x11 = 6x35x11 = 210x11 = 2310. Any multiple of this number "has the first five prime numbers as factors", but 2310 is the smallest such number.