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Q: What is the smallest number that has the first 5 prime numbers as its prime factors?

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Just multiply the first five prime numbers! 2x3x5x7x11 = 6x35x11 = 210x11 = 2310. Any multiple of this number "has the first five prime numbers as factors", but 2310 is the smallest such number.

27720

2310 has all of those as factors.

Just multiply the first three prime numbers together.

The smallest number divisible by first four prime numbers is 2x3x5x7 = 210.

120

The first three prime numbers are 2,3,5. The smallest number divisible by 2,3 and 5 is 30 (2*3*5).

The smallest three-digit number divisible by the first three prime numbers (2, 3, and 5) and the first three composite numbers (4, 6, and 8) is 120.

2310

It is 2520.

2520

120

11

Start counting from ' 1 '. The first number you name that is a member of the set is the smallest integer in the set.

12 is as it has 6 factors and is the smallest and first to have. Factors of 12= 1, 2, 3, 4, 6, and 12

first take the smallest number and then take the biggest number then the middle numbers well you must know how to count

4096 is the smallest number with exactly 13 factors. (Including 1 and itself as factors).192 is the smallest number with exactly 13 properfactors, (excluding the number itself).120 is the smallest number with at least 13 factors (it has 16 factors)To find the smallest number with exactly N factors (for example, N=12):Factor N into primes, (for example, 12= 2*2*3Subtract 1 from each of the prime factors (for example, 1,1,2)Sort them by largest first (for example, 2,1,1)Raise successive prime numbers to these powers (for example, 2^2,3^1,5^1)Multiply these together (for example: 4*3*5 = 60; 60 is the smallest number with exactly 12 factors).

101 is the first three-digit prime number.

2520 is the smallest multiple of of first ten natural numbers.

the answer is 120 because the first three prime numbers are 2,3,5 and the first three composite numbers are 4,6,8.

210 is the number whose prime factors are the first four primes unrepeated.

They are the first 26 numbers, starting with 2, such that their only factors are 1 and the numbers themselves.

Since you didn't specify a single number, and all numbers are multiples of themselves, the five smallest multiples are the counting numbers 1 to 5.

It is 2310.

multiply these prime numbers together to get your answer