Since odd numbers are in a ratio of 1:2 it means for every one odd there will be one even, there would be 50 odd numbers between 1-100, and 50 even numbers. So 50%.
50
100
Well i'm in 5th grade and i'm only learning about 1-100 prime factors...so here are the odd 1's from 1-100...3,57,11,13,,17,19,23,29,31,41,47,51,53,59,61,67,71,79,83,89,97:]
200
The sum of all the odd numbers from 1 through 100 is 10,000
The sum of the first 100 odd numbers (1 through 199) is 10000 (ten thou)
100
Since odd numbers are in a ratio of 1:2 it means for every one odd there will be one even, there would be 50 odd numbers between 1-100, and 50 even numbers. So 50%.
101
In Java:System.out.println("Even numbers")for (int i = 2; i
The sum of all odd numbers 1 through 99 is 9,801.
The sum of 5 odd numbers must be odd and 100 is even. So there cannot be such a set.
They are: 13579111315171921232527293133353739414345474951535557596163656769717375777981838587899193959799.
50
the answer is 2500 I am sorry but this answer is wrong. You only added the numbers between 1 and 100. The question is the first 100 odd numbers, you need to add 1 to 197. The correct answer is 10,000.
Look for a table of prime numbers. All the odd numbers that are NOT on this list are composite numbers.