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2 x 2 x 31 = 124

The prime factors are: 2 x 2 x 31

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Q: What are the prime factors of 124?
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Prime factorization of 124?

2x2x31=124


What are the factors and prime factors of 496?

factors: 1, 2, 4, 8, 16, 31, 62, 124, 248, 496prime factors: 2(4), 31Assuming that by "prime numbers of 496," you mean the prime factorization:24 * 31 or 2 * 2 * 2 * 2 * 31


What are the factors and prime factors of 248?

248 is a composite number because it has factors other than 1 and itself. It is not a prime number.The 8 factors of 248 are 1, 2, 4, 8, 31, 62, 124, and 248.The factor pairs of 248 are 1 x 248, 2 x 124, 4 x 62, and 8 x 31.The proper factors of 248 are 1, 2, 4, 8, 31, 62, and 124 or,if the definition you are using excludes 1, they are 2, 4, 8, 31, 62, and 124.The prime factors of 248 are 2, 2, 2, and 31. Note: There is repetition of these factors, so if the prime factors are being listed instead of the prime factorization, usually only the distinct prime factors are listed.The distinct prime factors (listing each prime factor only once) of 248 are 2 and 31.The prime factorization of 248 is 2 x 2 x 2 x 31 or, in exponential form, 23 x 31.NOTE: There cannot be common factors, a greatest common factor, or a least common multiple because "common" refers to factors or multiples that two or more numbers have in common. Factor tree:24862 431 2 2 2The prime factors of 248 are 2, 2, 2, and 31.The prime factorization of 248 is 2 x 2 x 2 x 31, which can also be represented as 23 x 31.


What is the prime factorization of 124 in family tree?

124 62,2 31,2,2


What is the sum of two prime numbers that equal 124?

How about: 101+23 = 124