Let's call n the first one
the problem is (n+1)2-n2=17 = 2n+1 then n = 8
The product between the consecutive prime numbers of 31 and 29 yield a result of 899.
The product of the prime numbers 19 and 23 is 437.
7and 5(7-5=2)
They are 29, 31 (899 = 29 x 31).
Any number greater than one can be co-prime. I guess the answer is 49.
8
15 and 16
62 and 63
12 and 13
12 and 13 (and you may note that 12+13 = 25)
The numbers are 13 and 14.
24 and 25, which are (49-1)/2 and (49+1)/2
The difference between the squares of two consecutive integers j and j+1 is |2j+1|. There are therefore two such pairs where this quantity is 17:-9 and -88 and 9
17 and 18
The numbers are 12 and 14.
The numbers are 12 and 14.
Consecutive numbers are whole numbers whose difference is 1.