The product between the consecutive prime numbers of 31 and 29 yield a result of 899.
The product of the prime numbers 19 and 23 is 437.
7and 5(7-5=2)
They are 29, 31 (899 = 29 x 31).
Any number greater than one can be co-prime. I guess the answer is 49.
8
15 and 16
62 and 63
The numbers are 13 and 14.
24 and 25, which are (49-1)/2 and (49+1)/2
The difference between the squares of two consecutive integers j and j+1 is |2j+1|. There are therefore two such pairs where this quantity is 17:-9 and -88 and 9
17 and 18
The numbers are 12 and 14.
The numbers are 12 and 14.
Let's denote the two consecutive numbers as x and x+1. The square of the first number is x^2, and the square of the second number is (x+1)^2. According to the given condition, their squares differ by 25, so we have the equation (x+1)^2 - x^2 = 25. Simplifying this equation, we get x^2 + 2x + 1 - x^2 = 25, which simplifies to 2x + 1 = 25. Solving for x, we find x = 12. Therefore, the two consecutive numbers are 12 and 13.
Consecutive numbers are whole numbers whose difference is 1.
9 and 6 9-6 = 3 92+62 = 117