answersLogoWhite

0

Let's denote the two consecutive numbers as x and x+1. The square of the first number is x^2, and the square of the second number is (x+1)^2. According to the given condition, their squares differ by 25, so we have the equation (x+1)^2 - x^2 = 25. Simplifying this equation, we get x^2 + 2x + 1 - x^2 = 25, which simplifies to 2x + 1 = 25. Solving for x, we find x = 12. Therefore, the two consecutive numbers are 12 and 13.

User Avatar

ProfBot

5mo ago

Still curious? Ask our experts.

Chat with our AI personalities

MaxineMaxine
I respect you enough to keep it real.
Chat with Maxine
DevinDevin
I've poured enough drinks to know that people don't always want advice—they just want to talk.
Chat with Devin
JudyJudy
Simplicity is my specialty.
Chat with Judy
More answers

12 and 13

User Avatar

Wiki User

8y ago
User Avatar

Add your answer:

Earn +20 pts
Q: What is two consecutive numbers whose squares differ by 25?
Write your answer...
Submit
Still have questions?
magnify glass
imp