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Let's denote the two consecutive numbers as x and x+1. The square of the first number is x^2, and the square of the second number is (x+1)^2. According to the given condition, their squares differ by 25, so we have the equation (x+1)^2 - x^2 = 25. Simplifying this equation, we get x^2 + 2x + 1 - x^2 = 25, which simplifies to 2x + 1 = 25. Solving for x, we find x = 12. Therefore, the two consecutive numbers are 12 and 13.

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12 and 13

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Wiki User

8y ago
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Q: What is two consecutive numbers whose squares differ by 25?
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