490
490
It is: 500
350,000
Yes, 6 is a factor of 492. If you divide 492 by 6 you get 82 with no remainder. The fact that there was no remainder means that the first number is a factor of the second number. Taking this to the obvious conclusion; the prime factors of 492 are 2, 2, 3, and 41. 6 is 2 times 3, so it is a non prime factor, but it is a factor nontheless.
The answer will depend on the degree to which the number is rounded. Without any indication of that, it is not possible to answer the question sensibly.
390
490
492. 4920 rounded to the nearest 100th place = 4900
490
500
It is: 500
To determine if 492 is divisible by a certain number, we need to check if 492 divided by that number results in a whole number without any remainder. 492 is divisible by 1, 2, 3, 4, 6, 12, 41, 82, 123, and 246. This is because these numbers are factors of 492, meaning they can be multiplied together to give 492.
Shaymin is number 492
350,000
163, 164, 165 let the three consecutive numbers be (n-1), n & (n+1). Then: (n-1) + n + (n+1) = 492 ⇒ 3n = 492 ⇒ n = 164 ⇒ the three numbers are 164-1 = 163, 164 & 164+1 = 165.
547,492 is.