Eight.
The number of digits required to store a number in binary is substantially greater than that required in octal and even larger than in hex.
32,767 characters in a standard text field.
use a loop(for or while) to get the input from the user then store each in the array using the Scanner class like this import java.util.Scanner;//before class declaration int[] Array = new int[10]; //just an example gets 10 ints from user Scanner input = new Scanner(System.in); then something like this for(int i = 0; i < 10;i++) { System.out.println("enter number:"); Array[i]= input.nextInt(); }
It is difficult to give an answer in terms of number of inches or total volume / number of bags required. For one thing, it depends on how deep the insulation is, i.e. it takes twice as much to make it 6 inches deep as it does to make it 3 inches deep. The deeper / thicker the insulation, the more it insulates. This is usually expressed as an "R-Value" where a higher value is more insulation. Note also that there are different kinds of blow-in insulation, e.g. fiberglass and cellulose. These have different properties and require different amounts to achieve the same thermal effect. One easy way to figure this out would be to go to the store where you plan to purchase the insulation and look at the bag. The bag will have a chart that shows the square footage or dimensions of the space to be insulated and the number of bags required to achieve various R-Values. If you know the company who manufactures the insulation, you can check their website. It is quite likely they have a similar chart of calculator as well.
Memory. It's the button that saves your current number, and when you press MRC, or Memory ReCall, the number is restored, giving you a great way to add two products if you have a basic calculator, or to do otherwise impossible equations that have many separate parts.
Count them: FF(16)=255(10)=11111111(2)
The number of digits required to store a number in binary is substantially greater than that required in octal and even larger than in hex.
Binary number system ,which has only two digits 0 and 1.
Yes, a byte is 8 bits, and a one hexadecimal digit takes up four bits, so two hexadecimal digits can be stored in a byte. The largest hexadecimal digit is F (which is 15 in base ten.) In base two, this converts to 1111, which takes up four bits, which is why it only takes four bits to store a hexadecimal digit. With 8 bits, two hexadecimal digits can be stored (FF would be 11111111, which is 8 bits), and 8 bits make up a byte. Generally, 4 bits are always used to store a hexadecimal digit, using leading zeros where necessary. For example, the hexadecimal digit 5 would be stored as 0101, and the hexadecimal digits 5A would be stored as 01011010.
Use the %X modifier of printf.Code Example:#include int main(void) { unsigned int iMyNumber = 255; printf("The number %u interpreted as hexadecimal is %X.\n", iMyNumber, iMyNumber); return 0; }
Write a program using the ADI instruction to add the two hexadecimal numbers 3AH and 48H and store the result in memory location 2100H
4
5
log(number of generations) / log(2) Round the answer up.
Probably 15, 16, or 17 would be the minimum but for a game store, i'm not so sure.
One example of a dollar store franchise is Dollar Tree. A minimum of a $125,000 investment is required. There are other dollar store franchises as well. http://www.businessfranchiseworld.com/dollar-tree-franchise/
5 times, as 4 1/2 would mean he got to the store and never came home or walked half way and then went home (either one resulting in him not having the last bottle of water). Thus, the minimum number of FULL trips he has to make is 5.