Count them: FF(16)=255(10)=11111111(2)
4
Use the %X modifier of printf.Code Example:#include int main(void) { unsigned int iMyNumber = 255; printf("The number %u interpreted as hexadecimal is %X.\n", iMyNumber, iMyNumber); return 0; }
four
You data has to be stored in the array arr[] of size 10.double min(const arr[], int arrSize){double minimum = arr[0];for (int j = 0; j < arrSize; j++){if (minimum > arr[j]){minimum = arr[j];}}return minimum;}
All data types can be used to store a whole number, even the data types that can store a decimal number.
Bytes can be written using hexadecimal, octal or decimal notation. A numeral with no prefix is always regarded as decimal. If prefixed with a leading zero it is deemed octal and if prefixed with 0x it is deemed hexadecimal. The following shows the three ways to write the decimal value 255: 255 (decimal) 0377 (octal) 0xff (hexadecimal) Hexadecimal is the generally the most convenient method of notation since each hexadecimal digit represents exactly 4-bits (a half byte or a nybble). An octal digit represents exactly 3 bits and is useful for notating bytes in groups of 3 bits. A 24-bit integer is both a multiple of 3 and 4 so it can be notated using 8 octal digits or 6 hexadecimal digits. Individual bytes are best stored using the uint8_t alias (defined in the <cstdint> standard library header) as this guarantees an 8-bit byte in the positive range 0 to 255 decimal. To store several contiguous bytes, use a vector of uint8_t: std::vector<uint8_t> bytes; bytes.push_back (255); bytes.push_back (0377); bytes.push_back (0xff); The above example pushes the value 255 onto the back of the vector three times, using decimal, octal and hexadecimal notation. You can also write contiguous bytes in multiples of 2, 4 and 8 bytes using uint16_t, uint32_t and uint64_t aliases respectively. Thus if you need a 64-bit value, use the uint64_t alias. uint64_t word = 0xffffffffffffffff; // maximum value
Eight.
The number of digits required to store a number in binary is substantially greater than that required in octal and even larger than in hex.
Binary number system ,which has only two digits 0 and 1.
Yes, a byte is 8 bits, and a one hexadecimal digit takes up four bits, so two hexadecimal digits can be stored in a byte. The largest hexadecimal digit is F (which is 15 in base ten.) In base two, this converts to 1111, which takes up four bits, which is why it only takes four bits to store a hexadecimal digit. With 8 bits, two hexadecimal digits can be stored (FF would be 11111111, which is 8 bits), and 8 bits make up a byte. Generally, 4 bits are always used to store a hexadecimal digit, using leading zeros where necessary. For example, the hexadecimal digit 5 would be stored as 0101, and the hexadecimal digits 5A would be stored as 01011010.
Use the %X modifier of printf.Code Example:#include int main(void) { unsigned int iMyNumber = 255; printf("The number %u interpreted as hexadecimal is %X.\n", iMyNumber, iMyNumber); return 0; }
Write a program using the ADI instruction to add the two hexadecimal numbers 3AH and 48H and store the result in memory location 2100H
4
5
log(number of generations) / log(2) Round the answer up.
Probably 15, 16, or 17 would be the minimum but for a game store, i'm not so sure.
One example of a dollar store franchise is Dollar Tree. A minimum of a $125,000 investment is required. There are other dollar store franchises as well. http://www.businessfranchiseworld.com/dollar-tree-franchise/
5 times, as 4 1/2 would mean he got to the store and never came home or walked half way and then went home (either one resulting in him not having the last bottle of water). Thus, the minimum number of FULL trips he has to make is 5.