6b
You can take 5 out of both of those, leaving 6b and 1.
9a4-b2=36a-2b=2(18-b) But if you meant 9a^4-b^2 it is not possible to factor
The GCF is a2b.
(3a + b)(3a - b)
6(b - ac + b2 - bc)
The polynomial IS b2 - 6b + 8.
b3 - 5b2 + 12 = (b - 2)(b2 - 3b - 6)Check:(b - 2)(b2 - 3b - 6)= b(b2 - 3b - 6) - 2(b2 - 3b - 6)= b3 - 3b2 - 6b - 2b2 + 6b + 12= b3 - 5b2 + 12
6(ab - ac + b2 - bc)
b2 - 7b - 6b = -4(-4)2 - 7(-4) - 6 = 16 +28 - 6 = 38
1080b3 + 5 = 5*(216b3 + 1) = 5*(6b + 1)(36b2 - 6b + 1)
6b
6b
(a - 7b)(a + 6b)
Oh, dude, it's like super easy. So, when you factor 6a 6b, you can take out the common factor, which is 6. Then you're left with a and b, so the factored form is 6ab. It's like math magic, but without the cool hat.
(6b + 7)(5b - 9)
a2-b2 = (a-b)(a+b)