If A and B have no common factors other than one, the LCM is their product.
1
(b-a)
LCM is the multiple of the highest power of prime factors in two or more numbers. Example: LCM of 9, 15, and 25 is 225, which is the multiple of the highest power of prime factors in 9, 15, and 25 (32 x 52).
It depends on whether or not a and c are coprime (have no factors in common). Suppose x is the greatest common factor of a and c, where x = 1 if a and c are coprime. ie GCF(a, c) = x then let a = x*m and c = x*n where m and n are coprime then LCM(ab, bc) = LCM(x*m*b, x*n*b) = x*m*n*b
If two numbers are expressed as ab and cb this is easier to work out. Assume that a and c have no common prime factors. Thus, the HCF of the two numbers will be b. The LCM is the two numbers multiplied by each other, divided by the HCF. So the LCM will be abc. b is a factor of abc, and so the HCF will always be a factor of their LCM.
Recall distributivity a(b + c) = ab + ac = (b + c)a and associativity (ab)c = a(bc) (a + b) + c = a + (b + c) as well as commutativity ab = ba a + b = b + a we are gonna need those. See for yourself when I applied each to learn the trick: ax - bx - ay + yb = (ax - bx) + (-ay + yb) = x(a - b) + -y(a - b) = (x - y)(a - b)
a and b are factors of ab
If these are vectors, then ba = - ab
NB, Nb
The GCF is ab
[(aa + bb) + (ab+ba)(aa+bb)*(ab+ba)]*[a + (ab+ba)(aa+bb)*b]
Yes.
Line BA
gcd(a,b) = 1, Since lcm is the multiple of a and b, a|lcm(a,b) =⇒ lcm(a,b) = ax b|lcm(a,b) =⇒ b|ax =⇒ ax = bq for q∈Z Since gcd(a,b) = 1,b |x and b≤x =⇒ ab ≤ ax ---→ (O1) However, ax is the least common multiple and ab is a common multiple of a and b, ax ≤ ab ---→ (O2) by (O1) and (O2) , ax = ab lcm(a,b) = ab
Yes, provided it is the ray. If AB is a vector then the answer is no.
AB and BA.
I think its BA.
yes it is
Yes.