It is x minus the complex conjugate of the first root. Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols and so it is not possible to make out what the factor given in the question is. It is therefore impossible to give a proper answer to your question. In future please submit your question spelling out the symbols as "plus", "minus".
x3-343
Since x3 is a factor of x5, it is automatically the GCF.
Greatest common factor of x4 and x3 is x3.
The greatest common factor of 1-x3 is 1, dummy.
X3 X(X2) X2(X) and, X * X * X
x3 - 2x2 + x - 2 =(x - 2)(x2 + 1)
x3 - 3x2 + x - 3 = (x2 +1)( x - 3)
(x2 + 1)(x - 3)
The question has a simple answer only if the polynomial has rational coefficients. However, the question does not state that it has rational coefficients so it is not valid to assume that is the case. So, suppose the third root is p. Then the polynomial is (x + 3)*(x - 3 + 2i)*(x - p) = (x2 + 2xi - 9 + 6i)*(x - p) = x3 + (2i - p)x2 - (2pi - 6i + 9)x + (9p + 6pi)
It is not possible to be sure about the answer because there is no sign before the linear term. If the polynomial is x3-4x2+x-4 then, the factors are (x-4) and (x2+1).
x(x + 2)(x - 5)
f(x)=x3-3x2-5x+39=(x+3)(x2-6x+13) It has three roots. One of which is x=-3. Using the quadratic equation: x = (6 +/- √(-16))/2 x = (6 +/- 4i)/2 = (3 +/- 2i) so, x=-3, x=3+2i, or x=3-2i
x3 + 5x2 - x - 5 = (x2 - 1)(x + 5) = (x + 1)(x - 1)(x + 5)
Yes, if there is no remainder after division, the divisor is a factor.
It is a polynomial if the square root is in a coefficient but not if it is applied to the variable. A polynomial can have only integer powers of the variable. Thus: sqrt(2)*x3 + 4*x + 3 is a polynomial expression but 2*x3 + 4*sqrt(x) + 3 is not.
seventh degree polynomial x3 times x4 = x7
Assuming you mean a fourth degree polynomial,P4 = x4 + 1P3 = x3 + 1P4*P3 = x7 + x4 + x3 + 1 is a seventh degree polynomial.