(x - 2)(2x + 3)
(2x - 3)(x + 2)
2x(x^2+x-6)
6x2 + 5x - 6 is factored out to (2x + 3)(3x - 2).
49x2 - 84x + 36 = (7x - 6)(7x - 6) or (7x - 6)2
Yes, but not in rational terms. The factorisation is: {x - [3-sqrt(57)]/6} * {x - [3+sqrt(57)]/6}
(2x - 3)(x + 2)
(x - 2)(2x - 3)
(x + 3)(3x - 2)
2x(x−6)(x+1)
2x^(2) + 72 Factors to 2( x^(2) + 36) s(x^(2) + 6^(2)) Does NOT factor. NB Remember . two squared terms with a positive(+) between them does NOT factor!!!! However, two squared terms with a negative(-) between DOES factor . e.g. x^(2) + 6^(2) Does NOT factor x^(2) - 6^(2) factors to ( x - 6)( x + 6 ) Note the different signs. Similarly 8^(2) + 6^(2) does NOT factor 8^(2) - 6^(2) factors to (8 - 6)(8 + 6) Or using the ~Pythagorean Equation. h^(2) = a^(2) + b^(2) Does NOT factors However, a^(2) = h^(2) - b^(2) factors to a^(2) = (h - b)(h + b) .
(2x - 3)(x + 2)
Notice that we can factor out 2x from both terms on the LH side: ... 4x2+6x=0. The greatest common factor of 4 and 6 is 2 . The greatest common factor of x2 and x ...
No
(2x+3)(x-2)
(2x + 3)(x - 2)
-4
2x(x^2+x-6)