(2x - 3)(x + 2)
2x(x^2+x-6)
6x2 + 5x - 6 is factored out to (2x + 3)(3x - 2).
49x2 - 84x + 36 = (7x - 6)(7x - 6) or (7x - 6)2
Yes, but not in rational terms. The factorisation is: {x - [3-sqrt(57)]/6} * {x - [3+sqrt(57)]/6}
(2x - 3)(x + 2)
(x - 2)(2x - 3)
2x^(3) - 10x^(2) - 12x '2' and 'x' are common factors , so take them out. Hence 2x(x^(2) - 5x - 6) Factor inside the brackets . 2x(x - 6)(x + 1) Done !!!!
Notice that we can factor out 2x from both terms on the LH side: ... 4x2+6x=0. The greatest common factor of 4 and 6 is 2 . The greatest common factor of x2 and x ...
(2x - 3)(x + 2)
No
(2x+3)(x-2)
(2x + 3)(x - 2)
-4
2x(x^2+x-6)
8
You would factor 2x2 + 7x + 6 into (2x + 3) (x+2)