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How do you determine the absolute value of a complex conjugate?
the absolute value of x + iy is equal to (x^2+y^2)^.5 and is the same for the conjugate, x-iy
The product of the complex numbers 4 3i 3 - 4i?
The easiest way to do this is treat i like a variable and multiply the binomials and combine like powers of i, then anywhere there is i², substitute it with (-1).So (4 + 3x)(3 - 4x) = {using FOIL} 4*3 - 4*4*x + 3*3*x - 3*4*x² = 12 -7x - 12x²So with x = i, you have 12 - 7i - 12*(i²) = 12 - 7i - -12 = 24 - 7iOne quick check to see if there is an error: The magnitude of the product of the two complex binomials will equal the product of the magnitude of each factor.Magnitude of a + bi = sqrt(a² + b²). The magnitudes of two numbers that are multiplied are: sqrt(4² + 3²) = 5, and sqrt(3² + (-4)²) = 5. The magnitude of the answer is sqrt(24² + (-7)²) = sqrt(576 + 49) = sqrt(625) = 25, which is 5 times 5.
What are the six steps of complex division?
1. Divide 2. Multiply (compare) 3. Subtract 4. Compare 5. Bring down 6. Start over
Plot -5 plus 9i in a complex plane?
Start where the x and y axes cross. Go 5 units to the left on the x (horizontal axis) and then go 9 units up from there. Put a dot in that spot.
Find the absolute value of the complex number z equals 3 plus 4i?
('|x|' = Absolute value of x) |3+4i| = √(32 + 42) = √(9+16) = √25 = 5 Thus |3+4i| = 5.
