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What is the empirical formula for a compound that is 43.6 percent phosphorus and 56.4 percent oxygen?
p2o5
75.7 percent arsenic and 24.3 percent oxygen what empirical formula would it have?
As2O3
What is the molecular formula of fructose with C 40 percent H 6.72 percent O 53.28 percent?
We assume 100 grams and turn those percentages into grams and find moles of species. 40 grams carbon (1 mole C/12.01 grams) = 3.33 moles C 6.72 grams hydrogen (1 mole H/1.008 grams) = 6.67 moles H 53.28 grams oxygen (1 mole O/16 grams) = 3.33 The smallest mole number is 1, so we have two small numbers. Divide the large number by the small. 6.67/3/33 = 2 so.............. CH2O is the empirical formula. You did not state that you had a quantity of this compound ( such as 60 grams, or whatever ), so the molecular formula can not be found from this info. C6H12O6 is of course the molecular formula. To find the molecular formula you need a mass of the compound aside from the simple percentages. Then you find, as we have done, the empirical formula. you divide the mass given by the mass of the empirical formula and then take that quotient and multiply it times the empirical formula. In this case (CH2O) * 6 = C6H12O6, the molecular formula
What is the empirical formula for 52.5 percent oxygen 25.4 percent phosphorus 22.1 percent aluminum?
Well first we assume a 100 g sample and then convert the elements into moles. We then divide them all by the number of moles that is the lowest of the 3. This procedure gives us AlPO4
A compound is found to consist of 34.9 percent sodium 16.4 percent boron and 48.6 percent oxygen what is its simplest formula?
Mol% or weight%? Weight percent seems more likely; let's assume that and see what we come up with. We'll assume 100g of the substance to make the numbers pretty; in that case we have: * 34.9 g Na / 23.0 g/mol Na = 1.52 mol Na * 16.4 g B / 10.8 g/mol B = 1.52 mol B (so far the weight percent is looking like a good assumption) * 48.6 g O / 16.0 g/mol O = 3.04 mol O (looking like a greatassumption) Converting that to small whole number ratios, we get an Na:B:O ratio of 1:1:2, so the empirical formula is NaBO2.
Empirical formula of a compound containing 60.3 percent magnesium and 39.7 percent oxygen?
The empirical formula of this compound would be MgO.
What is the percent composition of a compound with the empirical formula CO2?
The percent composition of a compound with the empirical formula CO2 is 27.3% carbon and 72.7% oxygen.
What is the empirical formula for a compound that is 43.6 percent and 56.4 percent oxygen?
The empirical formula for the compound that is 43.6% carbon and 56.4% oxygen is CO2. This is because the ratio of carbon to oxygen in carbon dioxide is 1:2.
What is the empirical formula for a compound that is 43.6 percent phosphorus and 56.4 percent oxygen?
p2o5
What is the empirical formula of a compound that is 40 percent sulfure and 60 percent oxygen?
The empirical formula of the compound with 40% sulfur and 60% oxygen is SO3 (sulfur trioxide). The ratio of sulfur to oxygen in the compound is 1:3, which simplifies to SO3.
What is the empirical formula of a compound that contains 32.39 percent sodium 22.53 percent sulfur and 45.07 oxygen?
The empirical formula of the compound is Na2SO4, which is sodium sulfate. This is because the percentages given closely correspond to the molar ratios in the compound, with a sodium to sulfur to oxygen ratio of 2:1:4.
A compound used to test for the presence of ozone in the stratosphere contains 96.2 percent thallium and 3.77 percent oxygen What is its empirical formula?
The molar mass of the compound is 444.8 g/mol. To find the empirical formula, we need to determine the number of moles of each element in the compound. The molar ratio of thallium to oxygen is approximately 3:1, so the empirical formula is TlO3.
What is the empirical formula for a compound that is 29.44 percent calcium 23.55 percent sulfur and 47.01 percent oxygen?
The empirical formula for this compound is CaSO4. This can be determined by converting the percentages to moles, finding the mole ratio, and simplifying the subscripts to the smallest whole number ratio.
What is the empirical formula of a compound that is 40 sulfur and 60 oxygen by weight?
The empirical formula for a compound with 40% sulfur and 60% oxygen by weight would be SO3 (sulfur trioxide). This is because the ratio of sulfur to oxygen is 1:3 in this compound.
75.7 percent arsenic and 24.3 percent oxygen what empirical formula would it have?
As2O3
What is the empirical formula for compound whose molecular formula is N2O4?
The empirical formula for a compound represents the simplest whole number ratio of atoms present in a molecule. For the molecular formula N2O4, the empirical formula is NO2 because it shows the simplest ratio of nitrogen and oxygen atoms present in the compound.
What is the empirical formula of a compound that is 40percent sulfur and 60percent oxygen by weight?
SO3
