Oh, dude, you're hitting me with some math lingo! So, like, the factor of 3c would just be 3, because it's the number that divides evenly into 3c. It's like the cool friend that 3c can always rely on to hang out with.
(8 - 3c)(8 + 3c)
5c^2(3c - 5)
(2a + 3)(b - 3c)
I don't know if this is correct or not but I think it is 7(3c-5). Can someone tell me if that is correct or not; thank you
9/3c=300/100c
(8 - 3c)(8 + 3c)
-((3c - 4)(3c + 4)(2c - 5)(2c + 5))
12bc - 4bd - 15xc + 5xd = 4b(3c - d) - 5x(3c - d) = (3c - d)(4b - 5x)
2ab - 6ac + 3b - 9c = 2a(b - 3c) + 3(b - 3c) = (2a + 3)(b - 3c).
5c^2(3c - 5)
(5c - 2)(c +1)
0
2ab - 6ac + 3b - 9c = b(2a + 3) - 3c(2a + 3) = (b - 3c)(2a + 3)
(c + 3)(c^2 - 3c + 9)
3(3c - 4)(c^2 + 2)
Ah, let's take a moment to appreciate the beauty of algebra. To factorise 6ab - 9ac, we can first factor out the greatest common factor, which is 3a. This leaves us with 3a(2b - 3c), where 2b - 3c is the factored expression. Just like painting a happy little tree, we've simplified our expression with a few gentle brushstrokes.
(2a + 3)(b - 3c)