(5c - 2)(c +1)
Wiki User
∙ 2009-05-13 11:07:09Yes
(a + 2b)(a + 2b)
There are 5C2 = 5*4/(2*1) = 10 combinations.
The only factor is 2. 2*(t3 + 2t2 + 4x)
Two is a prime factor of that equation.
The answer is 3C2*4C4*5C2 = [3 * 1 * (5*4)/(2*1)] = 3*1*10 = 30 ways.
Yes
-3c2
7c6
c = 4, c squared = 16, 3c squared = 48, 48 + 9 = 57.
he can choose the answer in this way, 5c1*5c3+5c2*5c2+5c3*5c1 evaluate, the answer will be 200.
5m
The other factor is 1.
Factor 2x plus 12x plus 28 is (x - 3)(x - 9)
(a + 2b)(a + 2b)
100 A rectangle is formed by 2 horizontal lines and 2 vertical lines. There are 5 horizontal and 5 vertical lines so the number of rectangles is 5C2 * 5C2 = 10 * 10 = 100
factor the trinomial 16x^2+24x+9