(5c - 2)(c +1)
The answer is 3C2*4C4*5C2 = [3 * 1 * (5*4)/(2*1)] = 3*1*10 = 30 ways.
-3c2
Yes
The value of (5C2) is calculated using the combination formula (nCr = \frac{n!}{r!(n-r)!}). Here, (n = 5) and (r = 2), so (5C2 = \frac{5!}{2!(5-2)!} = \frac{5!}{2! \cdot 3!} = \frac{5 \times 4}{2 \times 1} = 10). Thus, (5C2 = 10).
(a + 2b)(a + 2b)
The answer is 3C2*4C4*5C2 = [3 * 1 * (5*4)/(2*1)] = 3*1*10 = 30 ways.
7c6
-3c2
Yes
c = 4, c squared = 16, 3c squared = 48, 48 + 9 = 57.
he can choose the answer in this way, 5c1*5c3+5c2*5c2+5c3*5c1 evaluate, the answer will be 200.
5m
The other factor is 1.
(a + 2b)(a + 2b)
factor the trinomial 16x^2+24x+9
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
No. A monomial cannot have the variable c to different powers.