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x4 + x2 - 42
Let x2 = t, so that x4 = t2
t2 + t - 42 since -42 = 7(-6) and 7 + (-6) = 1, then
t2 + t - 42 = (t - 6)(t + 7) = (x2 - 6)(x2 + 7) By replacing t with x2. So we have,
x4 + x2 - 42 = (x2 - 6)(x2 + 7) = [x2 - (square root of 6)2](x2 + 7) = (x - sq. root of 6 )(x + sq. root of 6)(x2 + 7)
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