.04m2-n2=(.2m+n)(.2m-n)
-n(n + 10) or n(-n - 10)
The greatest common factor of the numbers 40 and 40 is 9.
8 is a factor of 40
The GCF of 10 and 40 is 10. 10 is a factor of 40, and 10 is the largest factor of itself, so 10 is the greatest common factor of 10 and 40.
2(n2+3n-54) 2(n+9)(n-6)
6n + 4 = 40(Minus 4 on both sides)6n = 40 - 46n = 36(Divide by 6 on both sides)n = 36/6= 6
7n3 + 6n = n*(7n2 + 6)
m^2 6n - 9n2 - 2m = (m - 3n)(m + 3n - 2)
factor by grouping 7m(m-2)+6n(2-m)
-mn(m - n2)(m + n2)
.6n - 1 = 23 .6n = 24 n = 40
M+6n
The GCF is 6.
(m + 2n)(m - 6n)
.04m2-n2=(.2m+n)(.2m-n)
Let the numbers be 'm' & 'n' Hence mn = -40 And m + n = 6 It follows m = 6 - n Substitute (6 - n) n = -40 6n - n^2 = -40 n^2 - 6n - 40 = 0 Factor (n - 10)(n + 4) = 0 n = 10 & n = -4 => m = 6 - - 4 = 10