Q: What is the factor of n2 - 6n - 40?

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.04m2-n2=(.2m+n)(.2m-n)

-n(n + 10) or n(-n - 10)

The greatest common factor of the numbers 40 and 40 is 9.

8 is a factor of 40

The GCF of 10 and 40 is 10. 10 is a factor of 40, and 10 is the largest factor of itself, so 10 is the greatest common factor of 10 and 40.

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2(n2+3n-54) 2(n+9)(n-6)

6n + 4 = 40(Minus 4 on both sides)6n = 40 - 46n = 36(Divide by 6 on both sides)n = 36/6= 6

7n3 + 6n = n*(7n2 + 6)

m^2 6n - 9n2 - 2m = (m - 3n)(m + 3n - 2)

factor by grouping 7m(m-2)+6n(2-m)

-mn(m - n2)(m + n2)

.6n - 1 = 23 .6n = 24 n = 40

M+6n

The GCF is 6.

(m + 2n)(m - 6n)

.04m2-n2=(.2m+n)(.2m-n)

Let the numbers be 'm' & 'n' Hence mn = -40 And m + n = 6 It follows m = 6 - n Substitute (6 - n) n = -40 6n - n^2 = -40 n^2 - 6n - 40 = 0 Factor (n - 10)(n + 4) = 0 n = 10 & n = -4 => m = 6 - - 4 = 10