Q: What is the factorization of the polynomial 121x2-22x 1?

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-(x + 5)(x + 6)

(x + 9)(x + 2)

13x(x+3x)

prime factorization of 89: 1 and 89

8a(5a2-1)

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We can't answer that without knowing what the polynomial is.

90

Several characters missing but I will hazard a gues and factorise 121x2 - 22x + 1 as (11x - 1)2

12

(x + 2)(3x + 1)

Start by looking for a common factor. Separate this factor, then factor the remaining polynomial.

-(x + 5)(x + 6)

(x + 9)(x + 2)

13x(x+3x)

5(x - 5)(x - 2)

Step 1: 2x.(x2 - 3x - 28) Step 2: 2x.(x - 7)(x + 4)

x3 - 7x2 + 6x =x (x2 - 7x + 6) =x (x - 6) (x - 1)