-(x + 5)(x + 6)
x2 -11x-12= (x-12)(x+1)
x2 + 11x + 18 (x + 9)(x + 2) CHECK: x2 + 9x + 2x + 18 x2 + 11x + 18 SET EACH EQUAL TO ZERO: x + 9 = 0 x = -9 x + 2 = 0 x = -2 NOW YOU ARE DONE: Solution set: {-9, -2}
The LCM is the absolute value of x.
x2 = -11x - 10 x2 + 11x + 10 = 0 (x + 1)(x + 10) = 0
It is (x+2)(x+9) when factored
-(x + 5)(x + 6)
3x2 + 33x + 54 =3(x2 + 11x + 18) = 3(x + 9)(x + 2)
x2 -11x-12= (x-12)(x+1)
X2 -11x +10=(x - 1 )(x - 10)
Do you mean x2+11x-26 if so then it is (x-2)(x+13) when factored
The actual equation itself is the polynomial. There is no polynomial for it, and your question doesn't really make sense.
Divide all terms by -1 so: x2-11x-26 = (x+2)(x-13) when factored
-(x + 13)(x - 2)
-x2 - 11x + 26 = -(x2 + 11x - 26) = -(x2 - 2x + 13x - 26) = -[ x(x - 2) + 13(x - 2) ] = -(x + 13)(x - 2) = (x + 13)(2 - x)
If you meant to write -x2 - 11x + 26, that factors to -(x - 2)(x + 13)
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