The GCF is b.
The GCF is b.
The GCF is a2b.
Here is a proof. Let a and b be any two real numbers. Consider the number x defined as x = ab + (-a)(b) + (-a)(-b). We can write this out differently as x = ab + (-a)[ (b) + (-b) ] Then, by factoring out -a , we find that x= ab + (-a)(0) = ab + 0 = ab. Also, x = [ a + (-a) ]b + (-a)(-b) And by factoring out b, we find that x=0 * b + (-a)(-b) = 0 + (-a)(-b) = (-a)(-b). Therefore x = ab and x = (-a)(-b) Then, by the transitivity of equality, we have ab = (-a)(-b).
In order to successfully factor you should follow these steps: 1.) Take out the GCF (ALWAYS DO THIS FIRST) 2.) Diff of Perfect Squares a^2-b^2=(a+b)(a-b) 3.) Diff/Sum of Cubes a^3+b^3=(a+b)(a^2-ab+b^2) a^3-b^3=(a-b)(a^2+ab+b^2) 4.) Key Number 5.) Grouping
The GCF is b.
The GCF is 27b.
b
The GCF is b.
# What are the possible blood types for the cross between the type B (BB or Bo?) male and AB female? # What are the possible blood types for the cross between the type B (BB or Bo?) male and AB female?
The GCF is a2b.
Yes, this will happen in a possibility with 50%.when AB and O give kids, the blood types of them will be :* 50% type A.* 50% type B.
15
30 + ab + 6b + 5a = 5(a+6) + b(a+6) = (b+5)(a+6)
Yes, it is possible for parents who are B positive to have an AB positive baby. This would occur if one parent is B positive with the genotype BO and the other parent is AB positive with the genotype AB. The child could inherit the A and B alleles from each parent, resulting in an AB blood type.
For sure 50% A and 50% B
The question cannot be answered. If AB is a line segment then A and B are normally the end-points of that segment. If A and B are points then A cannot be 5 and B cannot be 30 degrees. If A and B are not end-points of a line segment, it is not at all clear from the question what they are and how they relate to the line segment, AB.