Factor 7x2 - 9x - 10 = 0.
7 * -10 = -70
70 = 2 * 35 = 2 * 5 * 7
Factors of 70: 1,2,5,7,10,14,35,70
1 x 70 = 70
2 x 35 = 70
5 x 14 = 70
7 x 10 = 70
The sum should be negative, so the larger number in the sum must be negative.
product of -70 (sum of -9) :
1 + (-70) = -69
2 + (-35) = -33
5 + (-14) = -9
7 + (-10) = -3
The sums match up, so now we have the factors.
(x+5)(x+(-14)) = 0
(x+5)(x-14) = 0
However, the x2 must have a 7 in front of it, so divide the 14 by 7.
(7x+5)(x-2) = 0
And, if you have extra time, you can foil it back out to make sure you did it correctly.
7x2 - 14x + 5x -10 = 0
7x2 - 9x - 10 = 0
This confirms that the factorization is correct.
Finally, if you want to solve for x, just set each term equal to zero.
7x+5 = 0 or x-2 = 0
7x = -5 or x = 2
x = -5/7 or 2
7x2
9x2 + 9x - 10 =(3x - 2)(3x + 5)
if the x in "7x2" is variable x, then 7x(2)-5x=0 14x-5x=0 9x=0 x=0 if the x in "7x2" is a symbol for multiplication, then 7(2)-5x=0 14-5x=0 -5x= -14 5x=14 x= 14/5 x= 2 4/5 or, to factor it out... x(14-5)=0 x(9)=0 9x=0
factor out a 3x 3x(x-3)=3x2-9x
(7x + 4)(x - 5)
I suppose you mean, how do you factor it. 7x2 - 9x - 10 = (7x + 5)(x - 2).
(7x + 5)(x - 2)
21x2 + 27x - 30 = 3*(7x2 + 9x - 10) = 3*(7x2 - 5x + 14x - 10) =3*[x*(7x - 5) + 2*(7x - 5)] = 3*(7x - 5)*(x + 2)
7x2-9x-10 7*-10=-707x2-14x+5x-10=-70\........./.......\/7xx 2*7x...5x 2*57x(x-2)+5(x-2)=-70(x-2)(7x+5)=-70I forget how to do the rest. But I graphed it and the solution set is {-0.5,2}
7x2
With suitable signs between the terms, yes.
It is an algebraic expression of 3 terms
Step 1: Divide by 9x: 9x (x2 + 3x - 10) = 9x(x + 5)(x - 2)
9x2 + 9x - 10 =(3x - 2)(3x + 5)
(x - 10)(x + 1)
7x2 + 68xy - 20y2
10 + 9x