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You can take 7x2 out of both of those, leaving 5x4 and 1.

Q: What is the greatest common factor of 35x6 and 7x2?

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7x2-19x-6 7*6=427x2-2x+21x-6[7xx 2x] [3*7x 2*3]x(7x-2)+3(7x-2)Answer: (7x-2)(x+3)

14x2-7x2-16 7x2-16 (this can't be simplified any more)

(x - 2)(7x + 15)

x2 - 2x - 14 doesn't factor neatly. Applying the quadratic formula, we find two real solutions: 1 plus or minus the square root of 15x = 4.872983346207417x = -2.872983346207417

You need space between the numbers, I am guessing you mean 12 and 14 In which case you might factor the numbers 12=22 x3 14=7x2 So the LCM is 22 x3 x7 which is 21x4 or 84

Related questions

7x2

The GCF is x2

7x2 + 68xy - 20y2

Yes, they have the common factor of 7. 14 is 7x2, 35 is 7x5

(7x2 + 9)(4x - 1)

7(x2 + 7)

I suppose you mean, how do you factor it. 7x2 - 9x - 10 = (7x + 5)(x - 2).

1. 3x2+12= 3(x2+4) 2. 7x2+35x= 7x(x+5)

I suppose that would be 14x2 - 7x3. Just take out the common factor, 7x2. Divide each term by this factor to find the other factor.

(x - 3)(7x + 2)

(7x + 4)(x - 5)

(7x + 6)(x - 2)