using the quadratic formula -4/3 and -0.4
x2 + 8xy + 15y2 = (x + 3y) (x + 5y)
4x2 - 23xy + 15y2 = (4x - 3y)(x - 5y)
(x + 5y)(x - 3y)
If that's + 11, the answer is (15y - 11)(y - 1)
105y2z
30y2
using the quadratic formula -4/3 and -0.4
12y2+1+15y2-10y-18y=27y2-28y+1. contact at saqibahmad81@yahoo.com
3y*5y = 15y2
10y2 - 15y2 = -5y2
15y2 + 45y - 9 = 4y - 5y2; thus, 20y2 + 41y - 9 = (5y - 1)(4y + 9) = 0. Therefore, the solution to the equation given is, y = 1/5 or -2¼.