First you can factor a^2 from the first two terms and 4 from the last two terms.
(a^2)(a-2)+4(a-2)
You can see that they both have (a-2) as a factor.
So it is (a^2+4)(a-2)
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a3 - 2a2 + 4a - 8 = a2(a - 2) + 4(a - 2) = (a - 2)(a2 + 4)
the answer to factorising (a x a3 + 2ab + b2) would be (a4+2ab+b2)
kutta
a3+b3
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