64y2+144y+81???? or what is their gcf like this: 64y2=2x2x2x2x2x2xyxy??? If you respond to this and say the second one it is really very easy. All you have to do is break down the numbers like I did with 64y2 and then circle the numbers that are all the same. Then put together the circled numbers like 2xy2 (squared). Hope I helped!! If u have any questions ask me or a teacher or a friend! Sorry it's really long!
Oh and i wrote the beginning to this when I didnt have an account and then edited it so both accounts that wrote this were both me.
The only thing you can do to this is factor it... (4x + 8y)(4x - 8y)
Not sure which you mean, take your pick: (8y)3+27=(8y+3)((8y)2-3*(8y)+9)=(8y+3)(64y2-24y+9); or 8y3+27=(2y+3)(4y2-6y+9)
-28
9x2 + 48xy + 64y2 = (3x + 8y)2. Since it is a squared number cannot be a prime. We can say that as a perfect square number, it is formed by the sum of 1 and some prime numbers (excluded 2), i.e 1 + 3 + 5 + 7 + 11 + ... n, where n is a prime.