9x2 + 48xy + 64y2 = (3x + 8y)2. Since it is a squared number cannot be a prime. We can say that as a perfect square number, it is formed by the sum of 1 and some prime numbers (excluded 2), i.e 1 + 3 + 5 + 7 + 11 + ... n, where n is a prime.
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Answer this question…A. x4 + 2x3 + 9x2 + 4 B. x4 + 4x3 + 9x2 + 4 C. x4 + 2x3 + 9x2 + 4x + 4 D. x4 + 2x3 + 9x2 - 4x + 4
= 53 9x3 + 9x2 + 5x1+ 3x1 27 + 18 + 5 + 3
16? using 16, you have (3x2 + 4)(3x2 + 4) = 9x2 + 24x + 16
x=5
(-3x - 1)(3x - 7)