Since x3 is a factor of x5, it is automatically the GCF.
The GCF is x5
x5-1 = (x - 1)(x4 + x3 + x2 + 1)
To find the GCF of any set of numbers. Divide the numbers by their prime number factors, and see which is common to each number in the set. Hence 160,240 & 200. 160 = 2x2x2x2'x2'x5 200 = 2x2x2x5'x5 240 = 2x2x2x2'x3'x5 So each number has 2x2x2x5 (common to all three numbers) 2x2x2x5 = 40 The GCF. NB THe other factors are discrete to the given number. So for 200 the second '5' is discrete to 200 and so is not common to all the other numbers. I have written the discrete numbers as (2') etc.,
GCF of variables with exponents The GCF is the common variable with smallest exponent. example 9x4 - 27x6 the gcf is 9X4 because: 9x4 (1-3x2) = 9x4 - 27x6 In the same way: X5 is the GCF of X10 + x5 -x6 Because X5 ( X5 + 1 -x1) = X10 + x5 -x6 Remember the exponent rule if you are multiplyin the same base, you keep the base and add the exponents Hope this helps Btw this does not help me! anna
x times x times x times x times x
Choose the lowest of the exponents. The GCF of x3 and x5 is x3
The GCF is x5
14 ( x13, x5, x7)
The GCF is x5
The X5 has larger headlights than the X3.
x5-1 = (x - 1)(x4 + x3 + x2 + 1)
1.6667
-x(x2 - 2)(x2 + 3)
x5 = x3 times x2. In this case x3 = 64 so x = cube root of 64 ie 4
No, X5 and it's smaller sibling the X3 is made by Daimler Benz's German competitor BMW. The X5 is based on the 5 series and, not surprisingly, the X3 is based on the smaller 3 series.
example x5 + 6x4 + 9x3 To factor this expression, see if each "piece" of the expression has a variable in common. In this case, each piece has an X in common. Now we factor out the smallest exponent of X that we see in the expression. x3(x2+6x +9) You could factor the x squared +6x +9 also, into (x + 3)(x+3)
A power can be factored in many different ways; for example: x5 = x times x4 = x2 times x3. When such a power appears as a term in combination with other expressions, you should look out for common factoring patterns. Here are two examples: x2 + x5 Here, you can use the pattern "common factor". In this case, both parts have the common factor x2, so you can factor it out. x4 - 1 Here, you can use the pattern "difference of squares". Note that x4 is the square of x2, and 1 is the square of 1.