It depends upon the base of the number, but it is always one less than the base.
For decimal numbers (base 10), our usual numbers, the largest digit that can be used in 10 - 1 = 9.
A decimal number is simply a way of representing a number in such a way that the place value of each digit is ten times that of the digit to its right. It does not relate directly to weight.
18.19
99 is the largest two digit number. If I can use the digits anyway I want, then 9 to the 9th power is larger
A decimal number is simply a way of representing a number in such a way that the place value of each digit is ten times that of the digit to its right. A decimal representation does not require a decimal point. So the required decimal representation is 103, exactly as in the question.
44/22 = 2 so the decimal point should be placed after the first digit (which is a 1).
9
It depends on which base system you are using. If you use base 10 (the most common one which is used for most math) then any digit from 0 through 9 is acceptable for any given place value. The largest of these digits would be 9. If you are using a different base system then the answer will be different. For example, in base three the numbers 0 through 2 are acceptable for any one place value. The greatest digit in base three for a place value is 2.
Assuming you can use each digit only once, the logical answer has to be 9,876,543,210 (since you would want to use the largest numbers in the highest value places).
In the number 913256, the digit 9 is in the hundred-thousands place. Therefore, its value is 900,000.
You can use estimation and place value to help you figure out where to place the first digit.
You use place value for all decimal numbers that contain fractional parts. You also use place value for all decimal integers other than those containing only one-digit.
Each position has a so-called "place-value" which is 10 times as much as the position one to the right, and one-tenth the value of the position one to the left. Thus, the rightmost position in a whole number, or the rightmost position left of the decimal point, has a place-value of 1, the next position to the left has a place-value of 10, the next one has a place-value of 10 squared, the next one 10 cubed, etc.; the first digit TO THE RIGHT of the decimal point has a place-value of 1/10, the second one a place value of 1/100 (1 divided by 10 squared), etc.For the total value, each digit is multiplied by its place-value, and everything is added up. Normally you wouldn't actually do this calculation, but that's what the numbers we use really mean.
9 (in decimal). In any other base, it is (base-1)
The key to solving this kind of problem is to use the largest digit you possibly can, starting at the left. For example, the largest even digit is 8, so you start with an 8. For the next digit - the second from left - you can't repeat the 8, nor any odd digit, so you need to use the next-largest even digit.
Pressumably, you want to use each digit once. Starting from the left, use the largest digit you can every time. For example, the left-most digit should be "6".
The key to solving this kind of problem is to use the largest digit you possibly can, starting at the left. For example, the largest even digit is 8, so you start with an 8. For the next digit - the second from left - you can't repeat the 8, nor any odd digit, so you need to use the next-largest even digit.
A decimal number is simply a way of representing a number in such a way that the place value of each digit is ten times that of the digit to its right. It does not relate directly to weight.