It is: 60c
Alright, buckle up, buttercup. To find the least common multiple of 10ab and 14abc, you need to break down both numbers into their prime factors. The prime factors of 10ab are 2 * 5 * a * b, while the prime factors of 14abc are 2 * 7 * a * b * c. Now, the least common multiple will be the product of all the unique prime factors with the highest power they appear in either number. So, the least common multiple of 10ab and 14abc is 2 * 5 * 7 * a * b * c. Hope that clears things up for ya!
You need two numbers to find a least common multiple. The LCM (least common multiple) is the smallest positive whole number exactly divisible by two or more given whole numbers. The C in LCM stands for common and in general we only talk about common multiples of two or more numbers.You need at least two numbers to find an LCM.
The least common multiple (LCM) of two numbers is the smallest number that is a multiple of both numbers. In this case, the LCM of ab and bc would be the product of the two numbers divided by their greatest common divisor (GCD), which is b. Therefore, the LCM of ab and bc is abc.
The common multiples of 4 and 6 are any multiple of 12, which is their least common multiple. So the common multiples of 4 and 6 are the infinite set that starts 12, 24, 36, 48, 60, 72, 84, 96, 108, 120, 132, 144, 156, 168, 180, 192, 204, and so on.
Their product.
LCM(8, C, A) = 8*C*A.
a). The least common multiple of 4 and 6 is 12 . b). The least common multiple of 3 and 8 is 24 . c). The least common multiple of 2 and 12 is 12 . d). The least common multiple of 3 and 6 is 6 . Gosh, I guess they all have.
It is: 60c
Variables can be any number. The LCM possibilities are infinite.
C is this your homework??
5 c
You need two numbers to find a least common multiple. The LCM (least common multiple) is the smallest positive whole number exactly divisible by two or more given whole numbers. The C in LCM stands for common and in general we only talk about common multiples of two or more numbers.You need at least two numbers to find an LCM.
To answer that, you'll need to have a numerical value for the letters.
It is b: 80
We need the numbers more than we need the choices.
The answer is 8.