To answer that, you'll need to have a numerical value for the letters.
a). The least common multiple of 4 and 6 is 12 . b). The least common multiple of 3 and 8 is 24 . c). The least common multiple of 2 and 12 is 12 . d). The least common multiple of 3 and 6 is 6 . Gosh, I guess they all have.
It is b: 80
C is this your homework??
We need the numbers more than we need the choices.
Their product.
Alright, buckle up, buttercup. To find the least common multiple of 10ab and 14abc, you need to break down both numbers into their prime factors. The prime factors of 10ab are 2 * 5 * a * b, while the prime factors of 14abc are 2 * 7 * a * b * c. Now, the least common multiple will be the product of all the unique prime factors with the highest power they appear in either number. So, the least common multiple of 10ab and 14abc is 2 * 5 * 7 * a * b * c. Hope that clears things up for ya!
LCM(8, C, A) = 8*C*A.
To calculate the least common multiple (lcm) of decimals (integers) and fractions you first need to calculate the greatest common divisor (gcd) of two integers: int gcd (int a, int b) { int c; while (a != 0) { c = a; a = b % a; b = c; } return b; } With this function in place, we can calculate the lcm of two integers: int lcm (int a, int b) { return a / gcd (a, b) * b; } And with this function in place we can calculate the lcm of two fractions (a/b and c/d): int lcm_fraction (int a, int b, int c, int d) { return lcm (a, c) / gcd (b, d); }
The greatest common multiple of any set of integers is infinite.
Since variables can be any number, that could be any multiple of 5.
It is: 60c
A + B is also a multiple of C. ------------------------------------------- let k, m and n be integers. Then: A = nC as A is a multiple of C B = mC as B is a multiple of C → A + B = nC + mC = (n + m)C = kC where k = n + m kC is a multiple of C. Thus A + B is a multiple of C.