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The LCM of 3s and s^2 is 3s^2

Q: What is the least common multiple of the monomial a 3s and s2?

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The LCM of 12 and 18 is 36.The prime factors of 12 are 2, 2 and 3The prime factors of 18 are 2, 3 and 3.So, to calculate the lowest common multiple of the two numbers we need to include all the factors of each numberAs there is one 2 in 18 but two in 12, we need to have two 2s in the procedure.As there is one 3 in 12 but two in 18, we need to have two 3s in the procedure.This means that 2, 2, 3 and 3 need to be multiplied together to produce the LCM.2 x 2 x 3 x 3 = 36.The LCM is: 363636

The answer is 45 135=3x3x3x5 315=3x3x5x7 each number has at least 2 3s and one 5 3x3x5=45 Your welcome

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none duh if you said there is one you are either very dumb or very smart

The multiples of 6, 9, 15, and 18 are the infinite set of the multiples of their LCM, which is 90. So the common multiples of 6, 9, 15, and 18 are 90, 180, 270, 360, 450, 540, 630, 720, 810, 900, and so on.Explanation -- The LCMFirst, let's prime factorize each of the numbers:6: 2 x 39: 3 x 315: 3 x 518: 2 x 3 x 3We now need to calculate the least common multiple (LCM) of these numbers by making sure that each number's factors are represented (for example, 6 requires that there be at least one 2 and one 3; the 9 requires that there be at least two 3s).So we have 2 x 3 x 3 x 5.Note that included in the above are 2 x 3, 3 x 3, 3 x 5, and 2 x 3 x 5, each of the factors of the numbers.This gives us 2 x 3 x 3 x 5 = 90. Calculating other MultiplesThus the LCM (least common factor) is 90. To find other multiples we can calculate 90 * x where x can be any whole number.For example we can have2 x 90 = 180, so 180 is a multiple of 6, 9, 15, and 18.1.5 x 90 = 135, so 135 is a multiple.ExtensionWe can even extend this to a more algebraic problem:If c represents any whole number, then c x 90 = 90c would also be a whole number which would constitute it as a multiple

Related questions

You need at least two numbers to find an LCM.

2, 4, 6 3, 6 The LCM of 2 and 3 is 6.

The least common multiple of 14 18 and 27 is 378. To find the least common multiple of 14, 18 and 27 you first need to break them down into their prime factors: 14 = 2x7 18 = 2x3x3 27 = 3x3x3 The next step is to identify common factors. In this case two numbers have two 3s common, so we can disregard two 3s. Also, two numbers have a 2 common, so we can disregard one 2. The next step is to take every prime left (2, 7, 3, 3 and 3) and multiply them to get the LCM: 2x7x3x3x3 = 378 Thus the least common multiple of 14 18 and 27 is 378.

The factors of 64 are all 2s and the factors of 81 are all 3s. The greatest common factor is 1, since they have no factors in common. ■

The LCM of 12 and 18 is 36.The prime factors of 12 are 2, 2 and 3The prime factors of 18 are 2, 3 and 3.So, to calculate the lowest common multiple of the two numbers we need to include all the factors of each numberAs there is one 2 in 18 but two in 12, we need to have two 2s in the procedure.As there is one 3 in 12 but two in 18, we need to have two 3s in the procedure.This means that 2, 2, 3 and 3 need to be multiplied together to produce the LCM.2 x 2 x 3 x 3 = 36.The LCM is: 363636

The answer is 45 135=3x3x3x5 315=3x3x5x7 each number has at least 2 3s and one 5 3x3x5=45 Your welcome

If you want to find the LCM of two numbers, you first need to break those numbers down into their prime factors: 27=3x3x3 18=3x3x2 The next step is to discard the duplicate entries of any common prime factors. In this case, both numbers have two 3s in their prime factors, so we can discard 2 of these, leaving us with 3,3,3 and 2. Multiply all these together for the LCM: 3x3x3x2 = 54 So the lowest common multiple of 27 and 18 is 54.

3s + 1

This is a "least common multiple (LCM)" question in disguise. The prime factors of 16 are 2, 2, 2 and 2 The prime factors of 12 are 2, 2, and 3 The prime factors of 9 are 3 and 3 The prime factors of 10 are 2 and 5 So, the least common multiple (and any multiple) will have to have factors of * four 2s * two 3s * one 5 (2 x 2 x 2 x 2) x (3 x 3) x 5 = 16 x 9 x 5 = 720 To prove our findings * 720 ÷ 16 = 45 * 720 ÷ 12 = 60 * 720 ÷ 9 = 80 * 720 ÷ 10 = 72 These numbers will also evenly divide into any multiple of 720, such as 1,440, 2,160, 2,880 etc.

135=3s +15 120=3s 40=s

28 3s

how many 3s gointoo 33