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What is the least common multiple of 12 and 18?
The LCM of 12 and 18 is 36.The prime factors of 12 are 2, 2 and 3The prime factors of 18 are 2, 3 and 3.So, to calculate the lowest common multiple of the two numbers we need to include all the factors of each numberAs there is one 2 in 18 but two in 12, we need to have two 2s in the procedure.As there is one 3 in 12 but two in 18, we need to have two 3s in the procedure.This means that 2, 2, 3 and 3 need to be multiplied together to produce the LCM.2 x 2 x 3 x 3 = 36.The LCM is: 363636
The greatest common factor of 135 and 315?
The answer is 45 135=3x3x3x5 315=3x3x5x7 each number has at least 2 3s and one 5 3x3x5=45 Your welcome
What is a third as a decimal?
.33333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333..... the .3s go on
How many 3s are in 24?
none duh if you said there is one you are either very dumb or very smart
What are the common multiples of 6 9 15 and 18?
The multiples of 6, 9, 15, and 18 are the infinite set of the multiples of their LCM, which is 90. So the common multiples of 6, 9, 15, and 18 are 90, 180, 270, 360, 450, 540, 630, 720, 810, 900, and so on.Explanation -- The LCMFirst, let's prime factorize each of the numbers:6: 2 x 39: 3 x 315: 3 x 518: 2 x 3 x 3We now need to calculate the least common multiple (LCM) of these numbers by making sure that each number's factors are represented (for example, 6 requires that there be at least one 2 and one 3; the 9 requires that there be at least two 3s).So we have 2 x 3 x 3 x 5.Note that included in the above are 2 x 3, 3 x 3, 3 x 5, and 2 x 3 x 5, each of the factors of the numbers.This gives us 2 x 3 x 3 x 5 = 90. Calculating other MultiplesThus the LCM (least common factor) is 90. To find other multiples we can calculate 90 * x where x can be any whole number.For example we can have2 x 90 = 180, so 180 is a multiple of 6, 9, 15, and 18.1.5 x 90 = 135, so 135 is a multiple.ExtensionWe can even extend this to a more algebraic problem:If c represents any whole number, then c x 90 = 90c would also be a whole number which would constitute it as a multiple
