the answer is 13 the 4 prime numbers are 5,7,11,13 product of first three is 5*7*11=385 and,that of the last three is 7*11*13=1001,so the largest given prime is 13
If the two prime numbers are different: You get the two prime numbers, plus 1, plus the product. For example, if you multiply 2 x 3 = 6, the factors of 6 are 2, 3, 1, and 6. If the two prime numbers are the same: You get the prime number, 1, and the product. For example 2 x 2 = 4. The factors of 4 are 2, 1, 4.
210
That's a false statement. Both 16 and 64 have one prime factor. 16 can't be the LCM of two prime numbers and 64 can't be the product. If you leave out the word prime, you can use 16 and 4.
The smallest number divisible by first four prime numbers is 2x3x5x7 = 210.
Numbers that have 2 factors are prime numbers; Numbers that have 4 factors are either: * the cube of a prime; or * the product of two different primes; Numbers that have 8 factors are either: * a prime to the power 7; * the product of a prime cubed and different prime; * the product of three different primes.
No, because 28 can only be calculated as a product in the following ways: 1 x 28 2 x 14 4 x 7 In the above cases, 28, 14 and 4 are all non-prime numbers, which means that 28 cannot be a product of 2 prime numbers alone.
4
If the number is a product of two composite numbers, it must be 16, which is the product of 4 and 4. The prime factors of 16 are 2, 2, 2, and 2. The smallest composite number is 4, so the smallest possible product of two composite numbers is 4 x 4 = 16.
No - because the product of the first four prime numbers is equal to 2 x 3 x 5 x 7 = 210.
You had me until "product." The product of 4 digits can't be prime.
the answer is 13 the 4 prime numbers are 5,7,11,13 product of first three is 5*7*11=385 and,that of the last three is 7*11*13=1001,so the largest given prime is 13
2,3,5,7
The first four prime numbers after 875 are: 877, 881, 883, 887
The first four Mersenne prime numbers are 2, 3, 5, and 7.
532
As a product of its prime factors: 3*5*5*5 = 375