The first four prime numbers are 2, 3, 5, 7. The product of these numbers is 2 x 3 x 5 x 7 = 210
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the answer is 13 the 4 prime numbers are 5,7,11,13 product of first three is 5*7*11=385 and,that of the last three is 7*11*13=1001,so the largest given prime is 13
If the two prime numbers are different: You get the two prime numbers, plus 1, plus the product. For example, if you multiply 2 x 3 = 6, the factors of 6 are 2, 3, 1, and 6. If the two prime numbers are the same: You get the prime number, 1, and the product. For example 2 x 2 = 4. The factors of 4 are 2, 1, 4.
210
That's a false statement. Both 16 and 64 have one prime factor. 16 can't be the LCM of two prime numbers and 64 can't be the product. If you leave out the word prime, you can use 16 and 4.
The smallest number divisible by first four prime numbers is 2x3x5x7 = 210.