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Q: What is the product of the first 4 prime numbers?

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the answer is 13 the 4 prime numbers are 5,7,11,13 product of first three is 5*7*11=385 and,that of the last three is 7*11*13=1001,so the largest given prime is 13

210

If the two prime numbers are different: You get the two prime numbers, plus 1, plus the product. For example, if you multiply 2 x 3 = 6, the factors of 6 are 2, 3, 1, and 6. If the two prime numbers are the same: You get the prime number, 1, and the product. For example 2 x 2 = 4. The factors of 4 are 2, 1, 4.

That's a false statement. Both 16 and 64 have one prime factor. 16 can't be the LCM of two prime numbers and 64 can't be the product. If you leave out the word prime, you can use 16 and 4.

The smallest number divisible by first four prime numbers is 2x3x5x7 = 210.

Related questions

Numbers that have 2 factors are prime numbers; Numbers that have 4 factors are either: * the cube of a prime; or * the product of two different primes; Numbers that have 8 factors are either: * a prime to the power 7; * the product of a prime cubed and different prime; * the product of three different primes.

4

If the number is a product of two composite numbers, it must be 16, which is the product of 4 and 4. The prime factors of 16 are 2, 2, 2, and 2. The smallest composite number is 4, so the smallest possible product of two composite numbers is 4 x 4 = 16.

If the GCF of two numbers is 1, their LCM will be their product. Such numbers are called relatively prime, or co-prime. Any two prime numbers (like 3 and 5) will be that way, but the numbers don't have to be prime (like 4 and 9).

2,3,5,7

You had me until "product." The product of 4 digits can't be prime.

If the GCF of two numbers is 1, their LCM will be their product. Such numbers are called relatively prime, or co-prime. Any two prime numbers (like 3 and 5) will be that way, but the numbers don't have to be prime (like 4 and 9).

No - because the product of the first four prime numbers is equal to 2 x 3 x 5 x 7 = 210.

The first four prime numbers after 875 are: 877, 881, 883, 887

The first four Mersenne prime numbers are 2, 3, 5, and 7.

No, because 28 can only be calculated as a product in the following ways: 1 x 28 2 x 14 4 x 7 In the above cases, 28, 14 and 4 are all non-prime numbers, which means that 28 cannot be a product of 2 prime numbers alone.

the answer is 13 the 4 prime numbers are 5,7,11,13 product of first three is 5*7*11=385 and,that of the last three is 7*11*13=1001,so the largest given prime is 13

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