Best Answer

The smallest number divisible by first four prime numbers is 2x3x5x7 = 210.

Q: What is the smallest number divisible by 4 prime numbers?

Write your answer...

Submit

Still have questions?

Continue Learning about Basic Math

The first three prime numbers are 2,3,5. The smallest number divisible by 2,3 and 5 is 30 (2*3*5).

2 * 3 * 5 * 7 = 210 is the smallest one divisible by four unique prime numbers. However, there are an infinite number of them, since there are an infinite number of primes.

the least number is 210 which is divisible by four different prime numbers.

There aren't any prime numbers divisible by 4. Prime numbers aren't divisible by anything except 1 and the number.

the answer is 120 because the first three prime numbers are 2,3,5 and the first three composite numbers are 4,6,8.

Related questions

If it is a composite number, it is divisible by at least one prime number.

510510

The first three prime numbers are 2,3,5. The smallest number divisible by 2,3 and 5 is 30 (2*3*5).

2310

Because the four smallest prime numbers are 2, 3, 5, and 7. If you multiply these four together you get 210 (which makes 210 the smallest number divisible by four unique prime numbers).

101

2 * 3 * 5 * 7 = 210 is the smallest one divisible by four unique prime numbers. However, there are an infinite number of them, since there are an infinite number of primes.

Prime numbers are divisible because any numbers that are divisible are prime. If a number isn't divisible, it isn't prime. Prime numbers have to be divisible by at least one pair of numbers to be prime.

The smallest three-digit number divisible by the first three prime numbers (2, 3, and 5) and the first three composite numbers (4, 6, and 8) is 120.

7 is the smallest prime number which divides 539.

44,100

No prime numbers are divisible by 250. A prime number is only divisible by 1 and itself.