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The smallest whole number divisible by both 8 and 12 is 24.
If the last three digits of a number are divisible by 8, the whole number is divisible by 8.
To find the smallest number that has 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10 as factors, you need to find the least common multiple (LCM) of these numbers. The LCM is the smallest number that is divisible by all the given numbers. The LCM of 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10 is 2520. Therefore, 2520 is the smallest number that has 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10 as factors.
The smallest number evenly divisible by the numbers 1-12 is 60. 60 is also be by 0, but not by 13.
The least common denominator is the smallest whole number that can be divisible by two numbers. 4: 4, 8 8: 8 8 is the least common denominator for 4 and 8.