2520
It is 2520.
The smallest number divisible by first four prime numbers is 2x3x5x7 = 210.
The sum of the first 100 counting numbers (1-100) is 5,001.
The first three prime numbers are 2,3,5. The smallest number divisible by 2,3 and 5 is 30 (2*3*5).
2520
It is 2520.
2520
The smallest number divisible by first four prime numbers is 2x3x5x7 = 210.
The numbers that are divisible by two are infinite. The first four are: 2,4,6,8 . . .
The sum of the first 100 counting numbers (1-100) is 5,001.
The first three prime numbers are 2,3,5. The smallest number divisible by 2,3 and 5 is 30 (2*3*5).
The list of numbers that are divisible by 11 is infinite. The first four are: 11,22,33,44 . . .
11
The smallest three-digit number divisible by the first three prime numbers (2, 3, and 5) and the first three composite numbers (4, 6, and 8) is 120.
There are no top numbers. Suppose there was a top number that was divisible by two. Then that number plus two would be divisible by two and it would be bigger than the top number. So the first number could not have been a top number.
Oh, what a lovely question! Let's see, we can find the numbers divisible by 3 first, which are 33 numbers, and the numbers divisible by 7, which are 14 numbers. But wait, some numbers are divisible by both 3 and 7, so we must be careful not to count them twice. In the end, there are 47 numbers between 1 and 100 that are divisible by 3 or 7. Happy counting!