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Q: What is the sum of the proper factors of 256?

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The factors of 256 are: 1 2 4 8 16 32 64 128 256

The factors of 256 are 1, 2, 4, 8, 16, 32, 64, 128, and 256. Prime factors of 256 are 28. 256 = 28 so any splitting of this into two groups will work:

The only prime factor of 256 is: 2

256 = 28

The factors of 256 are 2, 2, 17, 8, 16, 92, 64, 128, and 256.The factor pairs of 256 are 1 x 256, 2 x 128, 4 x 64, 8 x 32, and 16 x 16.The prime factors of 256 are 2, 2, 2, 2, 2, 2, 2, and 2.The only distinct prime factor (listing each prime factor only once) is 2.The prime factors of 256 are 2x2x2x2x2x2x2x2x (or 28).

Related questions

48

A perfect number.

2,340

A perfect number is the term for a number that is equal to the sum of its proper divisors. Be careful not to confuse that with proper factors. Proper divisors include 1 but not the number itself. Proper factors don't include either I or the original number.

Deficient. The sum of its proper factors is 1+2+4+8+16+32+64+128+256+512 = 1023. Since that sum is less than 1024, it is deficient.

Abundant is a number for which the sum of all its proper factors is greater than the number itself. Deficient is a number for which the sum of all its proper factors is less than the number itself. Perfect is a number for which the sum of all its proper factors is the number itself.

Zero. 5 is a prime so its only factors are 1 and 5. It, therefore, has no proper factors.

an abundant number is less than the sum of its proper divisors

The sum is 14913.

The numbers for which the sum of its proper factors is 1 less than the number is the powers of 2; less than 50 these are: 2, 4, 8, 16 & 32.

2 + 5 + 10 + 25 = 42

No because a abundant # is a number where the sum of its proper factors is greater than itself. 16 is not an abundant number because the sum of its proper factors is (15) less than itself.

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