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It is (2 ^ 64) - 1.

Or UNSIGNED BIGINT Maximum value (databases)

2^64-1=18,446,744,073,709,551,615

it is the answer to the 'chessboard problem' using wheat or rice, dependent on what culture you believe the Chess board originated from, It also shows a quick view of exponential growth.

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Q: What is this number 18446744073709551615?
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What is the minimum amount of moves for 64 disks on tower of hanoi?

2^64-1 = 18446744073709551615


How can i name with words 9223372036854775808 and 18446744073709551615?

"um...i have no clue o_o" i have no clue ho to write my own answer lol so I'm improving that guy's^ eighteen quintillion, four hundred forty six quadrillion, seven hundred forty four trillion, seventy three billion, seven hundred nine million, five hundred fifty thousand, six hundred fifteen.


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A signed integer represents both positive and negative values, while an unsigned integer represents only positive values. Range depends on the number of bits the compiler assigns for the representation. bits max-negative max-positive max-unsigned 8 -128 +128 255 16 -32768 +32767 65535 32 -2147483648 +2147483647 4294967295 64 -9223372036854775808 +9223372036854775807 18446744073709551615


How do you compute the binary equivalent of a number using a recursive function using C or C plus plus?

Recursion is not the best way of dealing with this. An iterative function would be more efficient. However, the following recursive method will get the job done, if somewhat slowly and painfully (the equivalent iterative method is also shown, with performance timings for comparison): #include <Windows.h> #include <iostream> typedef unsigned long long UINT64; char * Dec2BinRecur( UINT64 Dec, char *Bin, size_t Length ) { if( Length ) { Bin[--Length] = Dec & 1 ? '1' : '0'; Dec2BinRecur( Dec >> 1, Bin, Length ); } return( Bin ); } char * Dec2BinIter( UINT64 Dec, char *Bin, size_t Length ) { while( Length ) { Bin[--Length] = Dec & 1 ? '1' : '0'; Dec >>= 1; } return( Bin ); } int main() { char strFormat[] = "Dec2Bin %I64u %s: %.2f microseconds Answer: %s\n"; LARGE_INTEGER Freq, Start, Finish; QueryPerformanceFrequency( &Freq ); double Recur, Iter; char Bin[65]; memset( Bin, 0, 65 ); memset( Bin, '0', 64 ); UINT64 Dec = 18446744073709551615; QueryPerformanceCounter( &Start ); Dec2BinRecur( Dec, Bin, 64 ); QueryPerformanceCounter( &Finish ); Recur = ( double ) ( Finish.QuadPart - Start.QuadPart ) / Freq.QuadPart; printf( strFormat, Dec, "Recursive", Recur * 1000000, Bin ); QueryPerformanceCounter( &Start ); Dec2BinIter( Dec, Bin, 64 ); QueryPerformanceCounter( &Finish ); Iter = ( double ) ( Finish.QuadPart - Start.QuadPart ) / Freq.QuadPart; printf( strFormat, Dec, "Iterative", Iter * 1000000, Bin ); return( 0 ); } Output: Dec2Bin 18446744073709551615 Recursive: 9.84 microseconds Answer: 1111111111111111111111111111111111111111111111111111111111111111 Dec2Bin 18446744073709551615 Iterative: 1.72 microseconds Answer: 1111111111111111111111111111111111111111111111111111111111111111


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